X-2>0⇒x>2
x-2<5⇒x<7
x∈(2;7)
x={3;4;5;6} 4целых решения
-32m³n² при m = - 0,5 , n = -1
-32 * (-0,5)³ * (-1)² = -32 * (-0,125) * 1 = 4
2*(сos^2x) - sin(3π/2 + x) = 0
2*(сos^2x) - cosx = 0
cosx(2cosx - 1) = 0
1) cosx = 0
x1 = π/2 + πn, n∈Z
2) cosx = 1/2
x = (+ -)arccos(1/2) + 2πk, k∈Z
x2 = (+ -)(π/3) + 2πk, k∈Z