Y'=(1/cos^2x)*(lnx)-(tgx)*(1/x)/ln^2x
^2 это вторая степень
3(2x+y)-26 = 3x-2y3*2x+3y-26 = 3x-2y-26 + 3y + 6x = 3x-2y-26 + 3y + 6x = -2y + 3x3y + 6x = 26 - 2y + 3x5y + 6x = 26 + 3xx = 26 + 3x / ((5y + 6x)/x)x = 26/3 - 5y/3
15-(x-3y) = 2x+515-x+3y = 2x+515 - x + 3y = 2x+5-x + 3y = -10 + 2x-3x + 3y = -10x = -10 / ((-3x + 3y)/x)x = 10/3 + y
А)1/2
б)1
в)0,25
г)8/11
д)16/13
е)18/7
2m(a-b)-3n(a-b)=(a-b)(2m-3n)