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Х³ + 9х² <span>+ 18х = 0
x </span>· (x² + 9x + 18<span>) = 0
произведение равно нулю, когда один из множителей равен нулю
x = 0 | </span>x<span>² + 9x + 18 = 0
| по теореме Виета:
| x</span>₁ + x₂ = -9
| x₁ * x₂ = 18
| x₁ = -3; x₂ = -6
Ответ: -6; -3; 0
1
4/7*x*7 3/7=x*(4/7*52/7)=208/49*x=4 12/49*x
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4/7*x=7 3/7
x=7 3/7:4/7
x=52/7*7/4
x=13
2
E=ma²
a=√(E/m) U a=-√(E/m)