Question

Сократите дробь:9a^2-9a+2/1-3a+b-3ab

Answer 1

9a²-9a+2=9(a-1/3)(a-2/3)=(3a-1)(3a-2)
D=81-72=9 a1=(9-3)/18=1/3 U a2=(9+3)/18=12/18=2/3

1-3a+b-3ab=(1-3a)+b(1-3a)=(1-3a)(1+b)

(3a-1)(3a-2)/(1-3a)(1+b)=-(3a-2)/(1+b)=(2-3a)/(1+b)