3(х-3)=4(х-4)
3х-9=4х-16
4х-3х=16-9
х=7
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Это означает, что нужно записать в виде двойного неравенства.![2)x=0,4\pm0,15\\\\0,4-0,15<x<0,4+0,15\\\\0,25<x<0,55\\\\4)x=0,73\pm0,01\\\\0,73-0,01<x<0,73+0,01\\\\0,72<x<0,74\\\\6)x=-2\frac{1}{5}\pm\frac{1}{10}\\\\x=-2,2\pm0,1\\\\-2,2-0,1<x<-2,2+0,1\\\\-2,3<x<-2,1](https://tex.z-dn.net/?f=2%29x%3D0%2C4%5Cpm0%2C15%5C%5C%5C%5C0%2C4-0%2C15%3Cx%3C0%2C4%2B0%2C15%5C%5C%5C%5C0%2C25%3Cx%3C0%2C55%5C%5C%5C%5C4%29x%3D0%2C73%5Cpm0%2C01%5C%5C%5C%5C0%2C73-0%2C01%3Cx%3C0%2C73%2B0%2C01%5C%5C%5C%5C0%2C72%3Cx%3C0%2C74%5C%5C%5C%5C6%29x%3D-2%5Cfrac%7B1%7D%7B5%7D%5Cpm%5Cfrac%7B1%7D%7B10%7D%5C%5C%5C%5Cx%3D-2%2C2%5Cpm0%2C1%5C%5C%5C%5C-2%2C2-0%2C1%3Cx%3C-2%2C2%2B0%2C1%5C%5C%5C%5C-2%2C3%3Cx%3C-2%2C1)
A3=A1+d(3-1)=A1+2d
A3=1-2*2= -3
Ответ: -3
Ответ:
Объяснение:
1)x^2 + y^2 - 4x - 6y + 14 = (x^2 - 2* x * 2 + 4 ) - 4 + (y ^ 2 - 2 * y * 3 + 9) - 9 + 14 = 1 + (x - 2)^2 + (y - 3)^2 > 0
2)4x^2 - 4xy + 5y^2- 12y + 10 =(4x^2 - 4xy + y^2) + (4y^2 - 12y + 9) - 9 + 10 =
= (2x - y)^2 + (2y - 3)^2 + 1 > 0