A) (x+π/3) ≤ π/3 + 2πk; k∈Z; x ∈[ 2π/3 +2πk; π/3 +2πk, k∈Z];
б) (3x - 2π/3) = 2π/3 +2πn;n∈Z; 3x = 4π/3 +2πn,n∈Z; x = 4π/9 +2πn/3,n∉Z;
3x = 5π/3+2πn, n∈Z; x = 5π /9 +2πn/3,n∈Z;
x∈ [5π/9 +2πn/3; 4π/9 +2πn/3;n∈Z]
Y`=(-3x²*x²-2x(6-x³))/x^4=(-3x^4-12x+2x^4)/x^4=(-x^4-12x)/x^4=-x(x³+12)/x^4=
=-(x³+12)/x³
x³=-12,x≠0
x=-∛12
- +
------------(-∛12)-----------
min
||x - 2| + 5| = 9
1) |x - 2| + 5 = 9 2) |x - 2| + 5 = - 9
|x - 2| = 4 |x - 2| = - 14
a) x - 2 = 4 решений нет
x = 6
б) x - 2 = - 4
x = - 2
Ответ : - 2 ; 6
Q=3:6 = 1/2
b4 = b1*q³ = 6*1/8 = 6/8= 3/4
S5 = b4(q^5-1)/(q-1) =
=3/4*(1/32-1)/(1/2 -1) = 3/4*(-31/32): (-1/2)= 3/4*31/32*2/1)= =93/64
Ответ: 64*S = 64*93/64 = 93