(х-5)*(х-6)=30
х^2-6х-5х+30=30
х^2-11х=0
х(х-11)=0
х=0. х=11
0,5*0,2+1/6*12=0,01+2=2,01............................
(√6-√14)(√6+√14) = <span>(√6)</span>² <span>- (√14)</span>² = 6 - 14 = -8
ответ -8
ctgx=1/tgx
tgx≠0
cosx≠0
sinx≠0
6tg²x-4tgx-2=0
3tgx-2tgx-1=0
D=4+12=16
tgx=-1/3 или tgx=1
x=arctg(-1/3)+πk или х=(π/4)+πn, k,n∈Z
О т в е т. arctg(-1/3)+πk ; (π/4)+πn, k,n∈Z