<span>(sin^2t*cos^2t+cos^4t) / (1-sin^4t-sint*cos^2t)=
=[cos</span>²t(sin²t+cos²t)]/[(1-sin²t)(1+sin²t)-sint*cos²t)]=
=cos²t/[cos²t(1+sin²t)-sint*cos²t]=cos²t/[cos²t(1+sin²t-sint)]=1/(1+sin²t-sint)
![\dfrac{(x-5)(2x^2-4x+2)}{x+3} \leq 0 \\ \dfrac{2(x-5)(x-1)^2}{x+3} \leq 0](https://tex.z-dn.net/?f=+%5Cdfrac%7B%28x-5%29%282x%5E2-4x%2B2%29%7D%7Bx%2B3%7D+%5Cleq+0+%5C%5C++%5Cdfrac%7B2%28x-5%29%28x-1%29%5E2%7D%7Bx%2B3%7D+%5Cleq+0+)
Применяем метод интервалов:
___+___(-3)___-___1____-____5___+___
![x \in (-3; 5]](https://tex.z-dn.net/?f=x+%5Cin+%28-3%3B+5%5D)
Целые решения: -2; -1; 0; 1; 2; 3; 4; 5
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