-(3х-1)-3(х+2)=-3х+1-3х-6=-6х-5
х=2
-6х-5=-12-5=-17
Ответ: х=-17
х+π/12=±arccos(√2/2)+2πk
x=-π/12±π/4+2πk
наибольший отрицательный корень
х=-π/12-π/4+2π*0=-π/3
![\frac{3tg63-3tg18}{1+tg63tg18}=3( \frac{tg63-tg18}{1+tg63tg18})=3tg(63-18)=3tg45=3 \\ sin \frac{ \pi x}{6} - \sqrt{3} cos \frac{ \pi x}{6} =2 \\ \sqrt{1^2+ (\sqrt{3})^2 } *( \frac{1}{\sqrt{1^2+ (\sqrt{3})^2 }} *sin \frac{ \pi x}{6}- \frac{ \sqrt{3} }{\sqrt{1^2+ (\sqrt{3})^2 } } *cos \frac{ \pi x}{6}) =2 \\ 2*( \frac{1}{2} *sin \frac{ \pi x}{6} - \frac{ \sqrt{3} }{2} *cos \frac{ \pi x}{6} )=2 \\ \frac{1}{2} *sin \frac{ \pi x}{6} - \frac{ \sqrt{3} }{2} *cos \frac{ \pi x}{6} = 1 \\ ](https://tex.z-dn.net/?f=+%5Cfrac%7B3tg63-3tg18%7D%7B1%2Btg63tg18%7D%3D3%28+%5Cfrac%7Btg63-tg18%7D%7B1%2Btg63tg18%7D%29%3D3tg%2863-18%29%3D3tg45%3D3+%5C%5C+%0Asin+%5Cfrac%7B++%5Cpi+x%7D%7B6%7D+-+%5Csqrt%7B3%7D+cos+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+%3D2+%5C%5C+%0A+%5Csqrt%7B1%5E2%2B+%28%5Csqrt%7B3%7D%29%5E2+%7D+%2A%28+%5Cfrac%7B1%7D%7B%5Csqrt%7B1%5E2%2B+%28%5Csqrt%7B3%7D%29%5E2+%7D%7D+%2Asin+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D-++%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B%5Csqrt%7B1%5E2%2B+%28%5Csqrt%7B3%7D%29%5E2+%7D+%7D+%2Acos+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D%29+%3D2+%5C%5C+%0A2%2A%28+%5Cfrac%7B1%7D%7B2%7D+%2Asin+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+-+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D+%2Acos+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+%29%3D2+%5C%5C+%0A+%5Cfrac%7B1%7D%7B2%7D+%2Asin+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+-+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D+%2Acos+%5Cfrac%7B+%5Cpi+x%7D%7B6%7D+%3D+1+%5C%5C+%0A)
Продолжение прикреплено в виде картинки:
U t S
велосипедист х 6ч 6х км
мотоциклист х+36 км/ч 2ч 2(х+36) км
6х = 2(х+36)
6х = 2х + 72
6х - 2х = 72
4х = 72
х= 72/4
х=18
Ответ: скорость велосипедиста 18 км/ч