3sin²(x/2)+sin(x/2)*cos(x/2)-2sin²(x/2)-2cos²(x/2)=0
sin²(x/2)+sin(x/2)cos(x/2)-2cos²(x/2)=0 (/cos²x/2≠0
(sin(x/2)/cos(x/2))²+sin(x/2)/cos(x/2)-2=0
tg²x/2+tgx/2-2=0
tgx/2=t
t²+t-2=0
t=1 t=-2
tgx/2=1 tgx/2=-2
x/2=π/4+πn x/2=-arctg2+πn
x=π/2+2πn x=-2arctg2+2πn
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. Если условие записано правильно, то значение выражения ЗАВИСИТ от m.
<span> x^3+x^2-4x-4=0
x^2(x+1)-4(x+1)=0
(x^2-4)(x+1)=0
x^2-4=0 или x+1=0
(x-2)(x+2)=0 x3=-1
x1=2
x2=-2
Ответ:-2;-1;2</span>
![\frac{3-x}{(4-x)(x+5)}\geq0\\\\\frac{x-3}{(x-4)(x+5)}\geq0\\\\x\neq4;x\neq-5](https://tex.z-dn.net/?f=%5Cfrac%7B3-x%7D%7B%284-x%29%28x%2B5%29%7D%5Cgeq0%5C%5C%5C%5C%5Cfrac%7Bx-3%7D%7B%28x-4%29%28x%2B5%29%7D%5Cgeq0%5C%5C%5C%5Cx%5Cneq4%3Bx%5Cneq-5)
- + - +
_________₀__________[3]_________₀________
- 5 4
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Ответ : x ∈ (- 5 ; 3] ∪ (4 ; + ∞)