Найдем, какие значение принимает 7а:
![\displaystyle \frac{7}5\ \textless \ a\ \textless \ 3.5\\\\\frac{7*7}5\ \textless \ 7a\ \textless \ \frac{7*7}2\\\\\frac{49}5\ \textless \ 7a\ \textless \ \frac{49}2](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cfrac%7B7%7D5%5C+%5Ctextless+%5C++a%5C+%5Ctextless+%5C++3.5%5C%5C%5C%5C%5Cfrac%7B7%2A7%7D5%5C+%5Ctextless+%5C+7a%5C+%5Ctextless+%5C+%5Cfrac%7B7%2A7%7D2%5C%5C%5C%5C%5Cfrac%7B49%7D5%5C+%5Ctextless+%5C+7a%5C+%5Ctextless+%5C+%5Cfrac%7B49%7D2)
Значения, которые принимает 2b:
![\displaystyle -2,5\ \textless \ b \ \textless \ - \frac{1}3\\\\-\frac{5*2}2\ \textless \ 2b\ \textless \ -\frac{2}3\\\\-5\ \textless \ 2b\ \textless \ -\frac{2}3](https://tex.z-dn.net/?f=%5Cdisplaystyle+-2%2C5%5C+%5Ctextless+%5C++b+%5C+%5Ctextless+%5C++-+%5Cfrac%7B1%7D3%5C%5C%5C%5C-%5Cfrac%7B5%2A2%7D2%5C+%5Ctextless+%5C+2b%5C+%5Ctextless+%5C+-%5Cfrac%7B2%7D3%5C%5C%5C%5C-5%5C+%5Ctextless+%5C+2b%5C+%5Ctextless+%5C+-%5Cfrac%7B2%7D3)
А теперь 7a-2b:
![\displaystyle \frac{49}5-(-5)\ \textless \ 7a-2b\ \textless \ \frac{49}2-\bigg(-\frac{2}3\bigg)\\\\\\\frac{49}5+\frac{5*5}5\ \textless \ 7a-2b\ \textless \ \frac{49*3}{6}+\frac{2*2}{6}\\\\\\\frac{74}{5}\ \textless \ 7a-2b\ \textless \ \frac{151}{6}\\\\\\14.8\ \textless \ 7a-2b\ \textless \ 25.1(6)\\\\\\15,\,\,\,16,\,\,\,17,\,\,\,18,\,\,\,19,\,\,\,20,\,\,\,21,\,\,\,22,\,\,\,23,\,\,\,24,\,\,\,25\\\\\\\text{OTBET}:\,\,11](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cfrac%7B49%7D5-%28-5%29%5C+%5Ctextless+%5C+7a-2b%5C+%5Ctextless+%5C+%5Cfrac%7B49%7D2-%5Cbigg%28-%5Cfrac%7B2%7D3%5Cbigg%29%5C%5C%5C%5C%5C%5C%5Cfrac%7B49%7D5%2B%5Cfrac%7B5%2A5%7D5%5C+%5Ctextless+%5C+7a-2b%5C+%5Ctextless+%5C+%5Cfrac%7B49%2A3%7D%7B6%7D%2B%5Cfrac%7B2%2A2%7D%7B6%7D%5C%5C%5C%5C%5C%5C%5Cfrac%7B74%7D%7B5%7D%5C+%5Ctextless+%5C+7a-2b%5C+%5Ctextless+%5C+%5Cfrac%7B151%7D%7B6%7D%5C%5C%5C%5C%5C%5C14.8%5C+%5Ctextless+%5C+7a-2b%5C+%5Ctextless+%5C+25.1%286%29%5C%5C%5C%5C%5C%5C15%2C%5C%2C%5C%2C%5C%2C16%2C%5C%2C%5C%2C%5C%2C17%2C%5C%2C%5C%2C%5C%2C18%2C%5C%2C%5C%2C%5C%2C19%2C%5C%2C%5C%2C%5C%2C20%2C%5C%2C%5C%2C%5C%2C21%2C%5C%2C%5C%2C%5C%2C22%2C%5C%2C%5C%2C%5C%2C23%2C%5C%2C%5C%2C%5C%2C24%2C%5C%2C%5C%2C%5C%2C25%5C%5C%5C%5C%5C%5C%5Ctext%7BOTBET%7D%3A%5C%2C%5C%2C11)
1) 56.483.972.572
2)103.067.025
3)39.008.016.000
Дана функция:
![f(x)=2x^3-5](https://tex.z-dn.net/?f=f%28x%29%3D2x%5E3-5)
Точка касания:
![x_0=-2](https://tex.z-dn.net/?f=x_0%3D-2)
Уравнение касательной имеет вид:
![y=f(x_0)+f'(x_0)(x-x_0)](https://tex.z-dn.net/?f=y%3Df%28x_0%29%2Bf%27%28x_0%29%28x-x_0%29)
Зная точку касания, то есть
![x_0](https://tex.z-dn.net/?f=x_0)
, найдём все неизвестные величины в формуле:
<u />
![f(x_0)=2*(-2)^3-5=2*(-8)-5=-16-5=-21](https://tex.z-dn.net/?f=f%28x_0%29%3D2%2A%28-2%29%5E3-5%3D2%2A%28-8%29-5%3D-16-5%3D-21)
![f'(x)=6x^2 \\ f'(x_0)=6*(-2)^2=6*4=24](https://tex.z-dn.net/?f=f%27%28x%29%3D6x%5E2+%5C%5C+f%27%28x_0%29%3D6%2A%28-2%29%5E2%3D6%2A4%3D24)
Теперь можно всё подставить в формулу:
<em>Ответ:
</em>
5a^2+5аb+5ac-5ab+5b^2+5bc-5ac-5bc+5c^2
5a^2+5b^2+5c^2
(√5-√3)/(√5+√3)=(√5-√3)(√5-√3)/(√5+√3)(√5-√3)=(5-2√15+3)/(5-3)=
=(8-2√15)/2=4-√15