A) (3x-2)/1
б) (12x-8)/2
B)(3x^2- 2x +3x -2)/x+1
1) 3x-3y+x²y-xy²<span>=
3(х-у) + ху(х-у)=
(3+ху)(х-у)
Ответ: </span>(3+ху)(х-у)
2) a³<span>-8 =
</span> a³-2³=
(a-2)(a²+2a+4)
Ответ: (a-2)(a²+2a+4)
2x - 8 = 0
2x = 8
x = 4
4x + 3 = 0
4x = - 3
x = - 3 /4 = - 0,75