Question

Решите уравение:9х2+2х-1/3=0

Answer 1

$9x^2+2x-1/3=0\\27x^2+6x-1=0\\ d=36-4*27*(-1)=144\\x=\frac{-6б\sqrt{144}}{54}\\x_1=\frac{-6+12}{54}=\frac{1}{9}\\x_2=\frac{-6-12}{54}=-\frac{1}{3}$