Question

решите уравнение0.3x^2+5x=2

Answer 1

3x^2+5x-2=0
D=b^2-4ac=(5)^2-4*3*2=25-24=1
x1=-b-кореньD/2a=-6/6=-1
x2=-2/3

Answer 2

0.3x^2+5x=2
0.3x^2+5x-2=0
3x^2+50x-20=0
D=2500+4*3*20=2740
$x1= \frac{-50+ \sqrt{2740} }{6}$
$x2= \frac{-50- \sqrt{2740} }{6}$