Question

(y^2-2y)^2-y^2(y+3)(y-3)+2y(2y^2+5)подробно распишите

Answer 1

$(y^{2}-2y)^{2}-y^{2}(y+3)(y-3)+2y(2y^{2}+5)=y^{4}-4y^{3}+4y^{2}-y^{2}(y^{2}-9)+4y^{3}+10y=y^{4}-4y^{3}+4y^{2}-y^{4}+9y^{2}+4y^{3}+10y=(y^{4}-y^{4})+(4y^{3}-4y^{3})+(4y^{2}+9y^{2})+10y=13y^{2}+10y$