<span> у=х^ tgx
lny=ln(</span>х^ tgx)
<span>
(1/y)y'=(tgx</span>·lnx)' y'=y·[(1/cos²x)·lnx+(tgx)/x] =(х^ tgx)[(lnx/cos²x)+(tgx)/x] <span>
</span>
4^2-3*4+c=0
16-12+c=0
c=-4
x^2-3x-4=0
D=9+16=25
x=(3+5)/2=4
x=(3-5)/2=-1
25*3*3*4*5*3=5*3*2*(15)^(1/2)=30*(15)^(1/2)
( х - 7 )^2 - 3x ( x + 5 )= x^2 - 14x + 49 - 3x^2 + 15x =-2x^2 -14x + 49= =2x^2 + 14x - 49
3x²-6x-75x+150=0
3x²-81x+150=0 I÷3
x²-27x+50=0 D=529
x₁=25 x₂=2.