1. х²=3, х=√3
2. у²-10=39
у²=39+10
у²=49
у=-7 и у=7 (2 решения)
3. 5t²-3=77
5t²=77+3
5t²=80
t²=16
t=-4 и t=4 (тоже 2 решения)
Решение
<span>а) -4+3i/-4-3i - -4-3i/-4+3i
</span>(-4+3i)/(-4-3i) = [(- 4 + 3i)*(-4 + 3i)]/[(- 4 - 3i)*<span>(- 4 + 3i)] =
</span>= - (16 - 24i + 9i²) / [(4 + 3i)*(- 4 + 3i)] = - (16 - 24i - 9) / [(3i)² - 4²] =
= - (7 - 24i) / (- 9 - 16) = (7 - 24i) / 25
(- 4 - 3i) / (- 4 + 3i) = [(- 4 - 3i)*(- 4 - 3i)] / [(- 4 + 3i)* (- 4 - 3i)] =
(16 + 24i + 9i²) / ((-4)² - 9i²) = (7 + 24i) / 25
(7 - 24i) / 25 - <span>(7 + 24i) / 25 = (7 - 24i - 7 - 24i) / 25 = - 48i / 25</span>
1)14-x=24-11x
14-x-24+11x=0
-10+10x=0
10x=10
x=1
2)6x-12=5x+4
6x-12-5x-4=0
x-16=0
x=16