Question

Найдите решение системы: 4(3х - 4у) + 14 = 3(5х + 2у) -2(х - 6у) = 5(3х - 4у) - 1

Answer 1

4(3х-4у)+14=3(5х+2у)

-2(x-6y)=5(3x-4y)-1

4(3x-4y)+14=3(5x+2y) 
12x-16y+14-15x-6*y=0

y=-(3*x-14)/22

-2(x-6y)=5(3x-4y)-1
-2(x-6*(-(3*x-14)/22))=5(3x-4*(-(3*x-14)/22))-1
-40//11x+84//11-195//11x+140//11+1=0

-235//11x+84//11+140//11+1=0

-235//11x+224//11+1=0

-235//11x+235//11=0

x=(235//11)/(235//11)

x=1

4(3*x-4y)+14=3(5*x+2y) 
4(3*1-4y)+14=3(5*1+2y) 

26-16y-3*(5+2y)=0

26-16y-15-6y=0

11-16y-6y=0
11-22y=0

y=-(-11)/22

y=11/22

y=0.5

 

Ответ: x=1; y=0.5.

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