Question

Найдите область определения функции y=log12(3x-12x) с подробным решением . Срочно!

Answer 1

3x² - 12x > 0
3x(x - 4) > 0
x(x - 4) > 0
        +                     -                            +
_________₀____________₀_____________
                    0                        4
\\\\\\\\\\\\\\\\\\\\\\                        //////////////////////////////
x ∈ (- ∞ , 0) ∪ (4 ; + ∞)

Answer 2

3x²-12x>0
3x(x-4)>0
x=0  x=4
+               _                    +
--------(0)-------------(4)---------
x∈(-∞;0) U (4;∞)