1) y'=2x+3;
2) y'=2*(2x)=4x;
Log_a (a^8 * b^3) = log_a a^8 + log_ab^3 = 8 + 3log_a b = = 8 + 3 * (log _b b / log_b a) = 8 + 3 * (1 / log_b a) =
= 8 + 3 * (1 / 0,2) = 8 + 3 * 5 = 8 + 15 = 23
(21x-5)-(15x+4) = 27
попробуем раскрыть скобки
21х-5-15х-4 = 27
21х-15х = 27+4+5
6х = 36
х = 36:6
х = 6
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проверим уравнение
(21*6-5)-(15*6+4) = 27
( 126-5 ) - ( 90 + 4 ) = 27
121 - 94 = 27
27 = 27
верно
<span>(8x+2)</span>²<span>-16x(4x+1)= 64x</span>²+32x+4-64x²-16x=16x+4.
x=1/12
16*(1/12)+4=16/12+48/12=64/12=16/3
Ответ: 5 целых 1/3.