Question

Найдите f'(2), если f(x) =

Answer 1

$f'(x) = \frac{1}{2 \sqrt{-3 x^{2} + 6x + 4} } * (-3 x^{2} +6x + 4)' = \frac{- 6x + 6}{2 \sqrt{-3 x^{2}+6x+4 } } =$$- \frac{3x -3}{ \sqrt{-3 x^{2}+ 6x + 4 } }$
$f'(2) = - \frac{3*2 - 3}{ \sqrt{-3*2 ^{2}+6*2+4 } } = - \frac{3}{2} = - 1,5$

Answer 2

F'(x)=(1/2) * (1/(√(-3x²+6x+4)))  *  (-6x+6) = (-3x+3) / (√(-3x²+6x+4))
f'(2) = (-3*2+3) / (√(-3*2²+6*2+4))=(-3)/(√(4))=-3/2=-1.5