Y=-3-4x
4x+y-y-x²=-3+6
-x²+4x-3=0
x²-4x+3=0
D=16-12=4
x1=(4-2)/2=1
x2=(4+2)/2=3
y1=-3-4=-7
y2=-3-12=-15
ответ: (1;-7); (3; -15)
1) (y - 4)(y + 2) - (y - 2)^2 = y^2 - 2y - 8 - y^2 + 4y - 4 = 2y - 12 = 2(y - 6)
2) <span>3х³у³-3х⁴у²+9х²у² = 3xy(xy - x^2 + 3)</span>
Y^3+(5-y)(25+5y+y^2)=y^3+5^3-y^3=5^3=125
2n-6/6 + n-2/3 - n+8/2 ∠ n-1 Я воспринимал <span>как</span>
(2n -6) / 6 +(n - 2) /3 - (n+8) /2 < n -1 ; || *6 ||
2n - 6 + 2(n -2) - 3(n+8) < 6(n - 1) ;
2n - 6 + 2n - 4 <span> - 3n - 24 < 6n </span>- <span>6 ;
</span>n - 34 < 6n -6
- 34 +6 < 6n -n ;
5n > - 28 ;
n > -5,6.
min( n ∈ Z ) = - 5.