2-5х>х+20
-х-5х>20-2
-6х>18
х>18:(-6)
х<-3
= 3*5х⁽³⁺²⁾*у⁽⁴⁺⁴⁾=15х⁵у⁸
Y`=(2*x∛x²+4/(x*x^(3/4))`=(2*x^(5/2)+4*x(-7/4))`=10*x(2/3)/3-7/(x^11/4).
y`=(√x-∛x)²`=(x^(1/2)-x^(1/3))²`=(x-2*x^(1/6)+x(2/3))`=
=1-5/(3*x(1/6))+2/(3*x^(1/3)).
Platit: 2 na 0 =1, tak kak 5 na 0 = 1, 10 na 0 = 1, poka a ne rovno 0 i a na 0 =1.
V našom priklade budet:
5-x = 2 na 0
5-x = 1, x = 5-1, x =4