∠BAK-∠DAK=24°⇒∠BAK=24°+∠DAK
∠CAB=∠CAD+∠DAK+∠BAK
AK - биссектриса⇒∠CAK=∠BAK=24°+∠DAK
∠CAB=∠CAK+∠BAK
∠CAB=2∠BAK=2(24°+∠DAK)=48°+2∠DAK
∠CAD+∠DAK+∠BAK=48°+2∠DAK
∠CAD=48°+2∠DAK-∠DAK-∠BAK
∠CAD=48°+∠DAK-∠BAK
∠CAD=48°+∠DAK-(24°+∠DAK)
∠CAD=48°+∠DAK-24°-∠DAK
∠CAD=48°-24°
∠CAD=24°
Ответ: А
М О
5005 49 58
5006 99 55
5011 <u>72 97</u>
5015 48 61
5018 <u>53 97</u>
5020 87 68
5025 98 75
5027 89 55
5029 55 53
5032 31 58
5041 66 33
5042 81 32
5043 54 59
5048 <u>57 96</u>
<span>5054 89 88
</span>
Ответ: 1) 3
<span>5(х-3)-3(3-х)²=5(х-3)-(х-3)²=(х-3)(5-3(х-3)=</span><span>(х-3)(5-3х+9)=(х-3)(14-3х)</span>
A+4/4a - a-2/a^2
a+a-a-2/a^2
2a-a-2/a^2
a-2/a^2
Ответ: a - 2/a^2