![A(-5;1;10)\\B(-5;15;-14)\\\\S( \frac{-5-5}{2}; \frac{1+15}{2}; \frac{10-14}{2})\\\\S(-5;8;-2)](https://tex.z-dn.net/?f=A%28-5%3B1%3B10%29%5C%5CB%28-5%3B15%3B-14%29%5C%5C%5C%5CS%28%20%5Cfrac%7B-5-5%7D%7B2%7D%3B%20%5Cfrac%7B1%2B15%7D%7B2%7D%3B%20%5Cfrac%7B10-14%7D%7B2%7D%29%5C%5C%5C%5CS%28-5%3B8%3B-2%29%20%20%20)
Ответ: Середина отрезка S(-5; 8; -2)
<span>arcsin(sin 3pi/7)=3pi/7</span>
![\log_{5-x}\frac{x+2}{(x-5)^4}\ge-4](https://tex.z-dn.net/?f=%5Clog_%7B5-x%7D%5Cfrac%7Bx%2B2%7D%7B%28x-5%29%5E4%7D%5Cge-4)
Область определения неравенства:
![1)\ 5-x>0,\\x<5;\\\\2) \ 5-x\ne 1\\x\ne4;\\\\3)\ \frac{x+2}{(x-5)^4}>0,\\x+2>0,\\x>-2;\\\\4)\ (x-5)^4\ne0,\\x\ne5.](https://tex.z-dn.net/?f=1%29%5C%205-x%3E0%2C%5C%5Cx%3C5%3B%5C%5C%5C%5C2%29%20%5C%205-x%5Cne%201%5C%5Cx%5Cne4%3B%5C%5C%5C%5C3%29%5C%20%0A%5Cfrac%7Bx%2B2%7D%7B%28x-5%29%5E4%7D%3E0%2C%5C%5Cx%2B2%3E0%2C%5C%5Cx%3E-2%3B%5C%5C%5C%5C4%29%5C%20%0A%28x-5%29%5E4%5Cne0%2C%5C%5Cx%5Cne5.)
— не удовлетворяет
![(*)\to](https://tex.z-dn.net/?f=%28%2A%29%5Cto)
нет корней.
![2)\ 5-x>1,\ x<4\ (**),\\\frac{x+2}{(x-5)^4}\ge (5-x)^{-4},\\x\ge-1](https://tex.z-dn.net/?f=2%29%5C%205-x%3E1%2C%5C%20x%3C4%5C%20%28%2A%2A%29%2C%5C%5C%5Cfrac%7Bx%2B2%7D%7B%28x-5%29%5E4%7D%5Cge%20%285-x%29%5E%7B-4%7D%2C%5C%5Cx%5Cge-1)
C учётом
![(**):\ \left \{ {{x<4} \atop {x\ge-1}} \right. ,\ -1\le x<4.](https://tex.z-dn.net/?f=%28%2A%2A%29%3A%5C%20%20%5Cleft%20%5C%7B%20%7B%7Bx%3C4%7D%20%5Catop%20%7Bx%5Cge-1%7D%7D%20%5Cright.%20%2C%5C%20-1%5Cle%20x%3C4.)
Отбор корней согласно области определения:
![\left \{ {{x<5,\ x\ne4,\ x>-2,\ x\ne5} \atop {-1\le x<4}} \right. ,\ \ \ -1\le x<4.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%3C5%2C%5C%20x%5Cne4%2C%5C%20x%3E-2%2C%5C%20x%5Cne5%7D%20%5Catop%20%7B-1%5Cle%20x%3C4%7D%7D%20%5Cright.%20%2C%5C%20%5C%20%5C%20%20-1%5Cle%20x%3C4.)
Ответ:
![x\in[-1;\ 4).](https://tex.z-dn.net/?f=x%5Cin%5B-1%3B%5C%204%29.)
Формула:
S квадрата=ab
a=x+2, b=2x+3
S квадрата=(x+2)(2x+3)
блин, ну, наверное так.