<h3>sin²(π - x) + cos(π/2 + x) = 0</h3><h3>sin²x - sinx = 0</h3><h3>sinx•(sinx - 1) = 0</h3><h3>1) sinx = 0 ⇔ x = πn, n ∈ Z</h3><h3>2) sinx = 1 ⇔ x = π/2 + 2πk, k ∈ Z</h3><h3><u><em>ОТВЕТ: πn, n ∈ Z ; π/2 + 2πk, k ∈ Z</em></u></h3><h3><u><em /></u></h3>
(x-1)²+x²+(x+1)²=2885
x²-2x+1+x²+x²+2x+1=2885
3x²+2=2885
3x²=2883 |÷3
x²=961
x₁=31 30, 31, 32
х₂=-31 -32, -31, -30
Ответ: 30, 31, 32; -32, -31, -30.
<span>tg (60°) = tg (π/3) = √3</span>