Question

Срочно! 2cos^2x-4cosxsinx=0

Answer 1

3сosx(cosx-2sinx)=0
cosx=0⇒x=π/2+πn,n∈z
cosx-2sinx=0/cosx
1-2tgx=0
tgx=1/2⇒x=arctg1/2+πk,k∈z

Вроде так

Answer 2

3сosx(cosx-2sinx)=0
cosx=0⇒x=π/2+πn,n∈z
cosx-2sinx=0/cosx
1-2tgx=0
tgx=1/2⇒x=arctg1/2+πk,k∈z