C^-12 / C^-17 = c^5 вроде так
...=а^2-7a-3a+21-6a^2+10a=-5a^2+0+21=-5a^2+21
<span>1/tg</span>²<span>x+1/Sinx+3=0
cos²x/sin²x + 1/sinx + 3 = 0</span>
<span>(cos</span>²<span>x
+ sinx + 3sin</span>²<span>x) / sin²x = 0,</span>
<span> sin
^2x ≠ 0, x ≠ </span>πk, k∈<span>Z; </span><span>
1 - <span> sin </span></span>²<span><span>x +
sinx + 3sin</span></span>²<span><span>x = 0
</span></span>2sin²x + sinx + 1 = 0
D < 0, решений нет
<span>1)2Cos</span>²<span>3</span>α <span>- Cos6</span>α = 2Cos²3α - 2Cos²α +1 = 1<span>
2) 2Cos</span>²α<span>/ 1+ Cos2</span>α= 2Cos²α/(1 + 2Cos²α -1) = 2Cos²α/2Cos²α = 1<span>
3) 1 - Cos (</span>π <span>- 2</span>α<span>)/ 1 - Sin</span>²α = 1+Cos2α/Сos²α= (1 +2Cos²α -1)/Cos²α =2<span>
4) Cos2 </span>α<span> + Sin</span>²α<span>/ 1 - Sin</span>²α= (Cos²α - Sin²α + Sin²α)/Сos²α = 1