Ответ:
Объяснение:
![\[\begin{gathered}{x^2}-6x-16>0\hfill\\{x^2}-6x-16=0\hfill\\D={b^2}-4ac=36+64=100\hfill\\{x_{1,2}}=\frac{{-b \pm \sqrt D}}{{2a}}=\frac{{6\pm \sqrt{100}}}{{2\cdot1}}=\frac{{6\pm 10}}{2}\hfill\\{x_1}=\frac{{6+10}}{2}=\frac{{16}}{2}=8\hfill\\{x_2}=\frac{{6-10}}{2}=\frac{{-4}}{2}=-2\hfill\\\end{gathered}\]](https://tex.z-dn.net/?f=%5C%5B%5Cbegin%7Bgathered%7D%7Bx%5E2%7D-6x-16%3E0%5Chfill%5C%5C%7Bx%5E2%7D-6x-16%3D0%5Chfill%5C%5CD%3D%7Bb%5E2%7D-4ac%3D36%2B64%3D100%5Chfill%5C%5C%7Bx_%7B1%2C2%7D%7D%3D%5Cfrac%7B%7B-b%20%5Cpm%20%5Csqrt%20D%7D%7D%7B%7B2a%7D%7D%3D%5Cfrac%7B%7B6%5Cpm%20%5Csqrt%7B100%7D%7D%7D%7B%7B2%5Ccdot1%7D%7D%3D%5Cfrac%7B%7B6%5Cpm%2010%7D%7D%7B2%7D%5Chfill%5C%5C%7Bx_1%7D%3D%5Cfrac%7B%7B6%2B10%7D%7D%7B2%7D%3D%5Cfrac%7B%7B16%7D%7D%7B2%7D%3D8%5Chfill%5C%5C%7Bx_2%7D%3D%5Cfrac%7B%7B6-10%7D%7D%7B2%7D%3D%5Cfrac%7B%7B-4%7D%7D%7B2%7D%3D-2%5Chfill%5C%5C%5Cend%7Bgathered%7D%5C%5D)
Отметим корни на числовой прямой и выясним знаки на полученных интервалах.
![\[\boxed{x\in(-\infty;-2)\cup(8;+\infty)}\]](https://tex.z-dn.net/?f=%5C%5B%5Cboxed%7Bx%5Cin%28-%5Cinfty%3B-2%29%5Ccup%288%3B%2B%5Cinfty%29%7D%5C%5D)
4*a^3*b* 12*(ab^2)^3 * 3a =
= 4*a^3*b * 12a^3*b^6 * 3a =
= 4*12*3*a^3*a^3*a*b*b^6 =
= 144a^(3 + 3 + 1) * b^(1 + 6) =
= 144*a^7*b^7
1.sin/1+cosa-sin/1-cosa= sina(1-cosa)+sina(1+cosa)/(1+cosa)(1+cosa)=sina-sinacosa+sina+sinacosa/1-cos^2a=2sina/sin^2a=2sina/sin^2a=2/sina