Question

(3x2-5)2-3(3x2-5)-10=0Решите квадратной уровнение 2 это квадрате

Answer 1

${(3 {x}^{2} - 5) }^{2} - 3(3 {x}^{2} - 5) - 10 = 0 \\ t = (3 {x}^{2} - 5) \\ {t}^{2} - 3t - 10 = 0 \\ t_1 = - 5, t_2 = 2$

$(3 {x}^{2} - 5) = 2 \\ 3 {x}^{2} = 7 \\ {x}^{2} = \frac{7}{3} \\ x = \pm \sqrt{ \frac{7}{3} }$

$(3 {x}^{2} - 5) = - 5 \\ 3 {x}^{2} = 0 \\ x = 0$