А(1;2;2)
O- начало координат, => O(0;0;0)
|OA|=3
![- 3 x = - 2 \\ x = \frac{ - 2}{ - 3} \\ x = \frac{2}{3}](https://tex.z-dn.net/?f=+-+3+x+%3D++-+2+%5C%5C+x+%3D+++%5Cfrac%7B+-+2%7D%7B+-+3%7D++%5C%5C+x+%3D++%5Cfrac%7B2%7D%7B3%7D+)
![5x = 0 \\ x = \frac{0}{5} \\ x = 0](https://tex.z-dn.net/?f=5x+%3D+0+%5C%5C+x+%3D++%5Cfrac%7B0%7D%7B5%7D++%5C%5C+x+%3D+0)
![0 \times x = 0](https://tex.z-dn.net/?f=0+%5Ctimes+x+%3D+0+)
х - любое число, т.к при умножении любого числа на ноль будет ноль
![6x - 13 = 3x + 10 \\ 6x - 3x = 10 + 13 \\ 3x = 23 \\ x = \frac{23}{3} \\ x = 7 \frac{2}{3}](https://tex.z-dn.net/?f=6x+-+13+%3D+3x+%2B+10+%5C%5C+6x+-+3x+%3D+10+%2B+13+%5C%5C+3x+%3D+23+%5C%5C+x+%3D++%5Cfrac%7B23%7D%7B3%7D++%5C%5C+x+%3D+7+%5Cfrac%7B2%7D%7B3%7D+)
F(x)= 2/(4-3x) +C;
F(1,5) = 1;
2 / (4 - 3*1,5) + C = 1;
2 /-0,5 + C = 1;
- 4 + C = 1;
C= 5.
F(x) = 2/(4-3x) + 5
А - 4
Б - 2
В - 3
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Решение смотри в приложении