Log3 (1/27) = log3 (3^(-3)) = - 3 log3(3) = - 3*1 = - 3
2х+3х+3у=11
5х+3у=11
х=1; у=2
3(х+2у)-у=27
3х+6у-у=27
3х+5у=27
у=3
х=4
7(х+3у)-6х=-59
х+21у=-59
у=-2
х=-17
4(х-у)-3х=23
х-4у=23
у=-5
х=3
3x-3+2-ax=0 -3x+3+2-ax=0
3x-ax-1=0 -3x-ax+5=0
x(3-a)=1 -x(3+a)=-5
далеше не догоняю
<span>sin5xcosx-cos5xsinx=0
</span>sin(5x-x)=0
4x=πN
x=πN/4
<u>a+5</u> + <u>a-2</u> = <u>4(a+5) + 3(a-2)</u> = <u>4a+20+3a-6</u> = <u>7a+14 </u>
3a 4a 12a 12a 12a