(x²-1)²+(x²-6x-7)²=0
[(x+1)(x-1)]²+[(x+1)(x-7)]²=0
(x+1)²[(x-1)²+(x-7)²]=0
(x+1)²(2x²-16x+50)=0
2(x+1)²(x²-8x+25)=0 D во второй скобке <0
x+1=0
х=-1
У =(1/3)*x -6 .
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а)
2/3 =(1/3)*x -6 ;
2 =x -18 ;
x =20.
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-0,5 =(1/3)*x -6 || *6 ;
-6*0,5 =1/3)*x*6 - 6*6 ;
-3 =2x -26 ;
x =16,5 .
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б)
y =x .
x =(1/3)*x -6 ;
3x =x -18 ;
x = - 9 . точка A(-9 ;9).
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в) x = -8.
y = 1/3)*x -6 ;
y = 1/3)*(-8) -6 ;
y = -8/3 -6 ;
y = -26/3. || - [8] (2/3) .
(74²-26²)\(61²-11²)=((74-26)(74+26))\((61-11)(61+11))=48·100\50·72=2·48\72=4\3
Ответ:4)
16 - 4а + а³- а⁴ = 16 - а⁴ - (4а - а³) = <span>4² - (а²)²</span> - а(4 - а²) = (4 - а²)(4 + а²) - а(4 - а²) =