24-40
x-100%
24*100/40=60%
Ответ:60%
168.
а) m*√x/√x*√x = m√x/x
б) 1*√2/√2*√2 = √2/2
в) 3*√c/5√c*√c = 3√c/5c
г) a*√3/2√3*√3 = a√3/2*3 = a√3/6
д) 5*√15/4√15*√15 = 5√15/4*15 = 5√15/60 = √15/12
169.
а) 4*(√3-1)/(√3+1)*(√3-1) = 4(√3-1)/√3-1 = 4
в) 1*(√х+√у)/(√х+√у)*(√х-√у) = √х+√у/х-у
д) 33*(7+3√3)/(7-3√3)*(7+3√3) = 33*(7+3√3)/49-27 = 3*(7+3√3)/2 = 21+9√3/2
б) 1*(1+√2)/(1-√2)*(1+√2) = 1+√2/1-2 = 1+√2/-1 = -1-√2
г) а(√а-√b)/(√a-√b)*(√a+√b) = a(√a-√b)/a-b
e) 15*(2√5-5)/(2√5+5)*(2√5-5) = 15*(2√5-5)/20-25 = -6√5 + 15
Ответ:
Объяснение:
2sin²x - 3√2cosx - 4 = 0
2(1 - cos²x ) - 3√2cosx - 4 = 0
2 - 2cos²x - 3√2cosx - 4 = 0
-2cos²x - 3√2cosx - 2 = 0
2cos²x + 3√2cosx + 2 = 0
Замена: cosx = t, t ∈ [-1 ; 1]
2t² + 3√2t + 2 = 0
D = 18 - 16 = 2
t₁ =
t₂ = ∉ [-1 ; 1]
cosx =
x = ±
На отрезке
x =
34^9
6^18=36^9
8^15=(2³)^15=2^45=(2^5)^9=32^9
32^9;34^9;36^9⇒8^15;34^9;6^18