По формуле квадрата суммы
(a-5)²+2(5-a)+1 = (5-a)²+2(5-a)+1 = (5-a +1)² = (6-a)² = (a-6)²
-2 < (4х-1)/5 (4х-1)/5 < 2
-10 < 4х-1 4х-1 < 10
-10+1 < 4х 4х < 10+1
-9 < 4х 4х < 11
-9/4 < х х < 11/4
-2,25 < x x < 2,75
-2,25 < x < 2,75
1) 9/4 - 15/12 = 9*3/12 - 15/12 = 27/12 - 15/12 = 12/12 = 1
y(-x)=1-cos(-x)/1+cos(-x)=1-cosx/1+cosx=y(x) четная
y(-x)=cos(-x-pi/2)-(-x)^2=cos(x+pi/2)-x^2=-cos(x-pi/2)-x^2
sqrt(1-2sinx)
-1<=sinx<=1
-2<=2sin2x<=2
3>=1-2sinx>=-1
[-1;3]
-sin x = - cos 2x
-sin x +1-2sin^2(x)=0
2a^2 +a -1 = 0
a = 1/2 a = -1
sin x = 1/2 , x = (-1)^n pi/6 +pin
sin x = -1 x = -pi/2 +2pin