Question

Выполните действия: m-4/m-m-3/m+1 ; y+3/4y(y-3)-y-3/4y(y+3) ; помогитеааааааааааааааа

Answer 1

$\frac{m-4}{m}- \frac{m-3}{m+1}= \frac{(m-4)(m+1)-m(m-3)}{m(m+1)}=$
$= \frac{m^2-3m-4-m^2+3m}{m(m+1)}=-\frac{4}{m(m+1)}$
$\frac{y+3}{4y(y-3)}- \frac{y-3}{4y(y+3)}=\frac{(y+3)^2-(y-3)^2}{4y(y-3)(y+3)}=$
$=\frac{y^2+6y+9-y^2+6y-9}{4y(y-3)(y+3)}=\frac{12y}{4y(y-3)(y+3)}=\frac{3}{(y-3)(y+3)}$