Ответ: решение во вложении.
Объяснение:
2cos(x-π/6)=√3
cos(x-π/6)=√3/2
cos(2π-(x-π/6) )=√3/2
x-π/6=arccos(√3/2)
cos(13π/6- x)=√3/2
x- π/6=π/6
13π/6 - x=arccos(√3/2)
x- π/6=π/6 + 2kπ, k ∈ z
13π/6 - x = π/6
x= π/3+2πk,kϵz
13π/6 - x=π/6+2πk,kϵz
x=2π-2kπ,kϵz
x=0+2πk,kϵz
x=2πk,kϵz