14g(p+2)−p−2=14gp+28g-p-2
(x-1)²<√2(x-1)
x-1=t ⇒
t²-(√2)t<0
t(t-√2)<0
-∞______+______0______-_______√2_______+______+∞
0<t<√2
0<x-1<√2
1<x<1+√2 ⇒
x∈(1;1+√2)
{(2х+1)2=3y;(x+2)=3y
{4х+2=3у;2х+4=3у
{2Х+2=o;y=o
}X=-1;y=o
![\sqrt{-a^2+25} \\ -a^2+25 \geq 0\\(-a+5)(a+5) \geq 0\\a_1=5\\a_2=-5](https://tex.z-dn.net/?f=+%5Csqrt%7B-a%5E2%2B25%7D+%5C%5C+-a%5E2%2B25+%5Cgeq+0%5C%5C%28-a%2B5%29%28a%2B5%29+%5Cgeq+0%5C%5Ca_1%3D5%5C%5Ca_2%3D-5)
- + -
-------[-5]-------[5]------
x∈[-5.5]
Ответ: наименьшее целое -5