Qsinx+1=0,cosx≠sinx⇒x≠π/4+πn,n∈Z
sinx=-1/q
1)нет решения
-1/q<-1
-1/q+1<0
(q-1)/q<0
q=1 U q=0
q∈(0;1)
-1/q>1
(q+1)/q<0
q=-1 U q=0
q∈(-1;0)
2)x=(-1)^(k+1)arcsin1/q+πk,k∈Z
(-1)^(k+1)arcsin1/q≠π/4
(9/(m²-3m+9)+2m/(3+m)-(m³-15m²)/(m³+27)=
9/(m²-3m+9)+2m/(3+m)-(m³-15m²)/[(m+3)(m²-3m+9)]=
=(9m+27+2m³-6m²+18m-m³+15m²)/(m³+27)=
=(m³+9m²+27m+27)/(m³+27)=(m+3)³/[(m+3)(m²-3m+9)=(m+3)²/(m²-3m+9)
ОДЗ:
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{x+7≥0 {x≥-7 ---[-7]-------------------->
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{x-2≥0 {x≥2 -------------[2]----------->
x≥2
Ответ: х=18