1).. а. (-x³y²)⁴*(3xy²)³ = x¹²y⁸*27x³y⁶ = 27x¹⁵y¹⁴
б. (3x + 5y)(5y - 3x) + (-3x - 5y)² = (5y)² - (3x)² + (3x+5y)² =
= 25y² - 9x² + 9x² + 30xy + 25y² = 50y² + 30xy = 10y(5y+3x)
2).. a. x⁴ - 125x = x(x³ - 5³) = x(x - 5)(x² + 5x + 25)
б. a² + 4ab + 4b² - 9 = (a + 2b)² - 3² = (a + 2b + 3)(a + 2b - 3)
Ответ: {2}
20a²-45b²=5·(4a²-9b²)=5·(2a-3b)·(2a+3b)