x>0 x^2-3x-40=0 x=(3+13)/2=8
ОДЗ :
1) 16 - 16x > 0
- 16x > - 16
x < 1
2) x² - 3x + 2 > 0
(x - 1)(x - 2) > 0
+ - +
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1 2
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3) x + 6 > 0
x > - 6
Окончательно : x ∈ (- 6 ; 1)
![log_{4}(16-16x)>log_{4}(x^{2}-3x+2)+log_{4}(x+6)\\\\log_{4}(16-16x)>log_{4}((x^{2}-3x+2)(x+6))\\\\16-16x>(x^{2} -3x+2)(x+6)\\\\16(1-x)-(x-1)(x-2)(x+6)>0\\\\16(1-x)+(1-x)(x-2)(x+6)>0\\\\(1-x)(16+(x-2)(x+6))>0\\\\(1-x)(16+x^{2}+4x- 12)>0\\\\(1-x)(x^{2}+4x+4)>0\\\\(x-1)(x+2)^{2}<0](https://tex.z-dn.net/?f=log_%7B4%7D%2816-16x%29%3Elog_%7B4%7D%28x%5E%7B2%7D-3x%2B2%29%2Blog_%7B4%7D%28x%2B6%29%5C%5C%5C%5Clog_%7B4%7D%2816-16x%29%3Elog_%7B4%7D%28%28x%5E%7B2%7D-3x%2B2%29%28x%2B6%29%29%5C%5C%5C%5C16-16x%3E%28x%5E%7B2%7D+-3x%2B2%29%28x%2B6%29%5C%5C%5C%5C16%281-x%29-%28x-1%29%28x-2%29%28x%2B6%29%3E0%5C%5C%5C%5C16%281-x%29%2B%281-x%29%28x-2%29%28x%2B6%29%3E0%5C%5C%5C%5C%281-x%29%2816%2B%28x-2%29%28x%2B6%29%29%3E0%5C%5C%5C%5C%281-x%29%2816%2Bx%5E%7B2%7D%2B4x-+12%29%3E0%5C%5C%5C%5C%281-x%29%28x%5E%7B2%7D%2B4x%2B4%29%3E0%5C%5C%5C%5C%28x-1%29%28x%2B2%29%5E%7B2%7D%3C0)
- - +
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- 2 1
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x ∈ (- ∞ ; - 2) ∪ ( - 2 ; 1)
Окончательный ответ с учётом ОДЗ :
x ∈ (- 6 ; - 2) ∪ (- 2 ; 1)
4-2х≤1-4х-1
-2х+4х≤-4
2х≤-4
х=-2
А) x=-2,5; y=2*(-2,5)-9=-5-9=-14; y=-14;
b)y=5; 2x-9=5; 2x=14; x=7;
в)x=-20; y=-70; -70=2*(-20)-9; -70=-49; нет