Решение
4^x - 3*2^x +2=0
(2^x)² - 3*(2^x) + 2 = 0
2^x = t , t > 0
t² - 3t + 2 = 0
t₁ = 1
t₂ = 2
2^x = 1
2^x = 2°
x₁ = 0
2^x = 2
x₂ = 1
Ответ: x₁ = 0 ; x₂ = 1
Q=a2/a1
q=-1/3:1/9=-1/3*9/1=-2
an=a1*q^(n-1)
an=1/9*(-3)^(n-1)
B/(a + b) : (1/(a - b) + 1/(a + b)) = b/(a + b) :(a + b + a - b)/(a + b)(a - b) = b/(a + b) : 2a/(a + b)(a - b) = b/(a + b) * (a + b)(a - b)/2a = b(a - b)/2a
4.3*(-2.7 - 4.3)/-2.7*2 = 4.3*7/5.4 = 301/54 = 5 31/54
B2+b3=b1q+b1q^2=b1(q+q^2)=30;
b4-b2=b1q^3-b1q=b1(q^3-q)=90;
(q+q^2)
----------- = 30/90;
(q^3-q)
(1+q)/((q-1)(q+1)) = 1/3;
1/(q-1)=1/3 => q-1=3; q=4.
b1(q+q^2)=30 => b1=30/20=1,5
Ответ: q=4; b1=1,5