Ответ:
Объяснение:1)=1+ctg²β=1/sin²β;
2)=(cosФ(cos²Ф-1))/cosФ -cos²Ф=cos²Ф-1-cos²Ф= -1;
3)=tg²α·sin²α/(sin²α(1/cos²α-1))=tg²α/tg²α=1.
= 0.25x^8 - 1.6x^4*y^3 + 2.56y^6
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Y(-π/6)=sin(-π/3)=-√3/2
y`=2cos2x
y`(-π/6)=2cos(-π/3)=2*1/2=1
Y=-√3/2+1(x+π/6)=x+π/6-√3/2 уравнение касательной
1)<span>5⁴*125²=9765625
2)</span>(-5² )³= (-5 )²*³ =-15625
3)9765625\(-15625) = -625