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Ответ: x∈(3;+бесконечность)
m-n+p(m-n)=(m-n)(1+p)
x+2a(x-y)-y=(x-y)+2a(x-y)=(x-y)(1+2a)
(a-b)²+a-b=(a-b)(a-b)+(a-b)=(a-b)(a-b+1)
4q(p-1)+(p-1)²=4q(p-1)+(p-1)(p-1)=(p-1)(4q+p-1)