Question

Интеграл 6z*2d/ (1-2z*3)*4 и произвести замену

Answer 1

$\int \frac{6z^2\, dz}{(1-2z^3)^4}=[\, t=1-2z^3\; ,\; dt=-6z^2\, dz\, ]=\\\\=\int \frac{-dt}{t^4}=-\int t^{-4}\, dt=-\frac{t^{-3}}{-3}+C=\frac{1}{3\cdot (1-2z^2)^3}+C$