Ответ:
-п/4
Объяснение:
1+cos2x=1+2sin2xcos2x
2cos2xsin2x-cos2x=0
cos2x=0 2x=П/2+Пk x=п/4+Пk/2 k=-1 П/4-п/2=-П/4
2sin2x=1 sin2x=1/2 2x=(-1)^kП/6+Пk
x=(-1)^kП/12+Пk/2 k=-1
x=-П/12-П/2
-1 ≤ Cosx ≤ 1 | * 3
-3 ≤ 3Cosx ≤3 | - 4
-7 ≤ 3Cosx - 4 ≤ -1
X=92 n=912
y=12 a=5
z=48 m=9
m=61 d=47
q=323 b=31
p=8 c=5
14х-2(х-1)+3(2х+6)= 14х-2х+2+6х+18= 18х+20
18х+20=0
18х=-20
х= -20
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18