Question

Решите уравнение. sin(п+x)=cos(-п/3)

Answer 1

$sin (\pi+x)=cos (-\frac{\pi}{3});\\\\-sin x=\frac{1}{2};sin x=-\frac{1}{2};x=(-1)^k*arcsin (-\frac{1}{2})+\pi*k;x=(-1)^{k+1}*\frac{\pi}{6}+\pi*k$

 

k є Z

Answer 2

-sinx=1/2

sinx=-1/2

$x=(-1)^n*(-\frac{\pi}{6})+\pi n\\\ x=(-1)^{n+1}*\frac{\pi}{6}+\pi n$