<span>2sin 2n/3- ctg n/6 =2*(√3/2) - √3 = √3 - √3 = 0</span>
![\left \{ {{y+2x=9} \atop {3x-5y=4}} \right. \left \{ {{y=9-2x} \atop {3x-5y=4}} \right. \left \{ {{y=9-2x} \atop {3x-5(9-2x)=4}} \right.](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7By%2B2x%3D9%7D+%5Catop+%7B3x-5y%3D4%7D%7D+%5Cright.+%5Cleft+%5C%7B+%7B%7By%3D9-2x%7D+%5Catop+%7B3x-5y%3D4%7D%7D+%5Cright.+%5Cleft+%5C%7B+%7B%7By%3D9-2x%7D+%5Catop+%7B3x-5%289-2x%29%3D4%7D%7D+%5Cright.+)
3x-5(9-2x)=4
3x-45+10x=4
13x=49
![x=3\frac{10}{13}](https://tex.z-dn.net/?f=x%3D3%5Cfrac%7B10%7D%7B13%7D)
![y=9-2*\frac{49}{13}\\ y=9-\frac{98}{13}\\ y=9-7\frac{7}{13}\\ y=\frac{117}{13}-\frac{98}{13}=\frac{19}{13}=1\frac{6}{13}\\](https://tex.z-dn.net/?f=y%3D9-2%2A%5Cfrac%7B49%7D%7B13%7D%5C%5C+y%3D9-%5Cfrac%7B98%7D%7B13%7D%5C%5C+y%3D9-7%5Cfrac%7B7%7D%7B13%7D%5C%5C+y%3D%5Cfrac%7B117%7D%7B13%7D-%5Cfrac%7B98%7D%7B13%7D%3D%5Cfrac%7B19%7D%7B13%7D%3D1%5Cfrac%7B6%7D%7B13%7D%5C%5C+)
Получаем, что данная система уравнения имеет решения
Вот, читай. Здесь вроде понятно написано.
(c+2)(c-3)=с²-3с+2с-6=с²-с-6
(5x-2y)(4x-y)=20х²-5ху-8ху+2у²=20х²-13ху+2у²
(2a-1)(3a+4)=6а²+8а-3а-4=6а²+5а-4
(a-2)(a-3x+6)=а²-3ах+6а-2а+6х-12=
=а²-3ах+4а+6х-12
(а+5)^2= а^2+10a+25
(3x-x)^2=9x^2-6x-x^2
(2b-1)(2b+1)=4b^2-1
(4a+3b)(4a-3b)=16a^2-9b^2