Решение
(4а-1/3х)•(-3х) = <span>(4a)*(-3x) - (1/3х)•(-3х) = - 12ax + 1</span>
Ответ:
4
Решение:
8x³-12x²y+6xy²-y³+12x²-12xy+3y², при x = 1,1; y = 1,2
8x³-12x²y+6xy²-y³+12x²-12xy+3y² = (2x-y)³+3(2x-y)²
- 8x³-12x²y+6xy²-y³ = 2³x³-3*2²*x²*y+3*2x*y²-y³ = (2x-y)³
- 12x²-12xy+3y² = 3(4x²-4xy+y²) = 3(2²*x²-2*2xy+y²) = 3(2x-y)²
(2x-y)³+3(2x-y)² = (2*1,1-1,2)³+3(2*1,1-1,2)² = 1³+3*1² = 1+3 = 4
1) 1*10^-3 m
2) 3*10^-11 m
3) 361*10^6 km^2
4) 22*10^3 km^2
5) 370*10^3 km^2
6)100 кДж
7) 9*10^-4 Дж
<span>мх+4у-12м=0
12-12м=0
12м=12
м=1</span>