Sin2α = 2SinαCosα
Cos²α = 1 - Sin²α = 1 - 25/169 = 144/169
Cosα = -12/13 ( Cos во II- й четверти <0)
Sin2α =2* 5/13 *(-12/13) = - 120/169
1) 0.2х+1.1х=1.4-2.7
1.3х=-1.3
х=1.3:1.3
х=-1
2) 5.4+3.6=0.3х+1.5х
9=1.8х
х=9:1.8
х=5
3) 1/8х-1/6х=10-15
-1/24х=-5
х=-5:(-1/24)
х=120